GEOMETRIA, TOPOLOGIA, TOPOGEOMETTRIA GRACELI TENSORIAL QUÂNTICA N-DIMENSIONAL

GEOMETRIA GRACELI SINTÉTICA.

$equação Graceli estatística tensorial quântica de campos$

$1 /$ $\psi ^{*}$ $G_{\mu \nu }\$ $T_{\mu \nu }$ G $T^{\nu }{}_{\alpha }$ $P^{\mu }\!$ /

$G_{\mu \nu }\$

$\psi ^{*}$

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$F [$ φ K] $q=\exp(2\pi iz)$ = $x=\sin \phi \,$ ; $K=F({\frac {1}{2}}\pi ,k)\,$ / $2i\pi \,$ φ + cos $2i\pi \,$ φ $K=F({\frac {1}{2}}\pi ,k)\,$ dt=

$equação Graceli estatística tensorial quântica de campos$

$1 /$ $\psi ^{*}$ $G_{\mu \nu }\$ $T_{\mu \nu }$ G $T^{\nu }{}_{\alpha }$ $P^{\mu }\!$ /

$G_{\mu \nu }\$

$\psi ^{*}$

//////

$F [$ φ K] $q=\exp(2\pi iz)$ = $x=\sin \phi \,$ ; $K=F({\frac {1}{2}}\pi ,k)\,$ / $2i\pi \,$ φ [z , τ ] + cos $2i\pi \,$ φ [z , τ ] $K=F({\frac {1}{2}}\pi ,k)\,$ dt =

$equação Graceli estatística tensorial quântica de campos$

$1 /$ $\psi ^{*}$ $G_{\mu \nu }\$ $T_{\mu \nu }$ G $T^{\nu }{}_{\alpha }$ $P^{\mu }\!$ /

$G_{\mu \nu }\$

$\psi ^{*}$

//////

$F [$ φ K] $q=\exp(2\pi iz)$ = $x=\sin \phi \,$ ; $K=F({\frac {1}{2}}\pi ,k)\,$ / $2i\pi \,$ φ + cos $2i\pi \,$ φ $K=F({\frac {1}{2}}\pi ,k)\,$ COS $\vartheta (z+1;\tau )=\vartheta (z;\tau ).$ dt =

$equação Graceli estatística tensorial quântica de campos$

$1 /$ $\psi ^{*}$ $G_{\mu \nu }\$ $T_{\mu \nu }$ G $T^{\nu }{}_{\alpha }$ $P^{\mu }\!$ /

$G_{\mu \nu }\$

$\psi ^{*}$

//////

$F [$ φ K] $q=\exp(2\pi iz)$ = $x=\sin \phi \,$ ; $K=F({\frac {1}{2}}\pi ,k)\,$ / $2i\pi \,$ φ [z , τ ] + cos $2i\pi \,$ φ [z , τ ] $K=F({\frac {1}{2}}\pi ,k)\,$ COS $\vartheta _{00}(z;\tau )=\vartheta (z;\tau )$ dt=

$equação Graceli estatística tensorial quântica de campos$

$1 /$ $\psi ^{*}$ $G_{\mu \nu }\$ $T_{\mu \nu }$ G $T^{\nu }{}_{\alpha }$ $P^{\mu }\!$ /

$G_{\mu \nu }\$

$\psi ^{*}$

//////

$F [$ φ K] $q=\exp(2\pi iz)$ = $x=\sin \phi \,$ ; $K=F({\frac {1}{2}}\pi ,k)\,$ / $2i\pi \,$ φ + cos $2i\pi \,$ φ $K=F({\frac {1}{2}}\pi ,k)\,$

COS ${\begin{aligned}\vartheta _{01}(z;\tau )&=\vartheta \!\left(z+{\textstyle {\frac {1}{2}}\pi };\tau \right)\\[3pt]\vartheta _{10}(z;\tau )&=\exp \!\left({\textstyle {\frac {1}{4}}}\pi i\tau +\pi iz\right)\vartheta \!\left(z+{\textstyle {\frac {1}{2}}}\tau ;\tau \right)\\[3pt]\vartheta _{11}(z;\tau )&=\exp \!\left({\textstyle {\frac {1}{4}}}\pi i\tau +\pi i\!\left(z+{\textstyle {\frac {1}{2}}}\right)\right)\vartheta \!\left(z+{\textstyle {\frac {1}{2}}}\tau +{\textstyle {\frac {1}{2}}};\tau \right).\end{aligned}}$ = dt

$equação Graceli estatística tensorial quântica de campos$

$1 /$ $\psi ^{*}$ $G_{\mu \nu }\$ $T_{\mu \nu }$ G $T^{\nu }{}_{\alpha }$ $P^{\mu }\!$ /

$G_{\mu \nu }\$

$\psi ^{*}$

//////

$F [$ φ K] $q=\exp(2\pi iz)$ = $x=\sin \phi \,$ ; $K=F({\frac {1}{2}}\pi ,k)\,$ / $2i\pi \,$ φ [z , τ ] + cos $2i\pi \,$ φ [z , τ ] $K=F({\frac {1}{2}}\pi ,k)\,$ COS ${\begin{aligned}\theta _{1}(z;q)&=-\vartheta _{11}(z;\tau )\\\theta _{2}(z;q)&=\vartheta _{10}(z;\tau )\\\theta _{3}(z;q)&=\vartheta _{00}(z;\tau )\\\theta _{4}(z;q)&=\vartheta _{01}(z;\tau )\end{aligned}}$ dt =